Originally posted by TwoWheelTerror
I've had a thought.. if you multiply .9r by 10 it'll have a zero on the end..
x = .9999999....
10x = .999999....0
does this mean that .9r cannot equal 1
No, there is no zero, because the sequence of 9's never ends. If you don't want to think about it like that, instead think that "times 10" shifts the decimal point to the right, not the numbers to the left. This you have the same sequence of 9s, just the decimal point moved right. No zero at the end, no difference between 0.9r and 1

Thats nowhere near a
proper explaination, but perhaps the best way of thinking about it if you don't like infinities.
/edit
Anyway, I'm off to sleep, I've lectures at 9, 10 and 11 tomorrow morning, and 2 1 hour supervisions in the afternoon. I await Mr Reece's explaination why every single "assumption" in maths must be proved every single time its used, given proofs are constant, and once true are always true

That and his proof of 1>0, since I'm sure he uses that a lot, so has proved it countless times and he can reel off quickly. Shouldn't take more than a few hundred pages of PhD level mathematics to prove every result he uses in that proof too
