edexcel maths m1 question?

mayesford said:
I'm a bit confused, with why the 3.13 is equal to the initial velocity but the initial is 0
Click to expand...

Before A starts moving, the only contribution to momentum is from particle B which has a velocity of 3.13... and a mass of 0.5. Particle A has a velocity of 0 at this point so it has no momentum.

When A starts moving, both A and B have momentum. The sum of their momentums must equal the momentum from before due to conservation of momentum.
 
Yea, I know the formula for two parties that jerk or collide , which is ,
m1u1+m2u2 = m1v1+m2v2, but the questions says for particle B , u = 0, but is it that only for its horizontal velocity
 
mayesford said:
Yea, I know the formula for two parties that jerk or collide , which is ,
m1u1+m2u2 = m1v1+m2v2, but the questions says for particle B , u = 0, but is it that only for its horizontal velocity
Click to expand...

That's only for the horizontal velocity. We know it's vertical velocity to be 3.13, because you worked it out earlier using v^2 = u^2 + 2as. :)
 
You must log in or register to reply here.
Back
Top Bottom