Simple: find x in terms of r from the equation linking p, x, and r (taking p as constant), then substitute into the equation for A, differentiate with respect to r to maximise A, then plug in your value of p.
Simple: find x in terms of r from the equation linking p, x, and r (taking p as constant), then substitute into the equation for A, differentiate with respect to r to maximise A, then plug in your value of p.
Simple: find x in terms of r from the equation linking p, x, and r (taking p as constant), then substitute into the equation for A, differentiate with respect to r to maximise A, then plug in your value of p.
Surely you just create an equation from the area and perimeter equations and then differentiate to get radius which maximises area and then plug in the radius.
Any decent A-level Maths student should be able to do this.
edit: lemme check if youve done it right
edit: I get x = r = 4.2007 which corresponds to A = 63.011
x being equal to r is also intuitive if you are maximising a rectangle.
Simple: find x in terms of r from the equation linking p, x, and r (taking p as constant), then substitute into the equation for A, differentiate with respect to r to maximise A, then plug in your value of p.
Im guessing it involves rearranging into a formula, differentiation to find turning points, then again to find if it's a MAXIMA/Minima value, plug numbers back in. Ta-dah!
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