16 Jan 2007 at 15:46 #1 touch touch Soldato Joined 28 Oct 2006 Posts 12,465 Location Sufferlandria I need to find the inverse of a function. Its been a good year or two since i did my higher maths and im not sure i remember it correctly. f(x) = 4x + 3 so the inverse is 1/4x -3 ?
I need to find the inverse of a function. Its been a good year or two since i did my higher maths and im not sure i remember it correctly. f(x) = 4x + 3 so the inverse is 1/4x -3 ?
16 Jan 2007 at 15:55 #2 Visage Visage Permabanned Joined 13 Jan 2005 Posts 10,708 touch said: I need to find the inverse of a function. Its been a good year or two since i did my higher maths and im not sure i remember it correctly. f(x) = 4x + 3 so the inverse is 1/4x -3 ? Click to expand... if the inverse of f(x) is f'(x) then f(f'(x)) = x. So, to check your example: 4(1/4x-3) + 3 = 1/x -12 + 3 = 1/x -9. So your answer is wrong. EDIT: I've assumed that by 1/4x you mean 1 divided by 4x, as opposed to x divided by 4. Either way the answer is incorrect, though... Last edited: 16 Jan 2007
touch said: I need to find the inverse of a function. Its been a good year or two since i did my higher maths and im not sure i remember it correctly. f(x) = 4x + 3 so the inverse is 1/4x -3 ? Click to expand... if the inverse of f(x) is f'(x) then f(f'(x)) = x. So, to check your example: 4(1/4x-3) + 3 = 1/x -12 + 3 = 1/x -9. So your answer is wrong. EDIT: I've assumed that by 1/4x you mean 1 divided by 4x, as opposed to x divided by 4. Either way the answer is incorrect, though...
16 Jan 2007 at 16:03 #3 Dave Dave Soldato Joined 30 Oct 2004 Posts 4,956 Location Sacramento, CA, USA Using the "interchanging variables" method: (swap variables around and solve for y) y = 4x + 3 Changing variables: x = 4y + 3 (x - 3) / 4 = y Therefore f^-1(x) = (x - 3) / 4 Test: if x = 2, f(x) = 11 f^-1(11) = 2
Using the "interchanging variables" method: (swap variables around and solve for y) y = 4x + 3 Changing variables: x = 4y + 3 (x - 3) / 4 = y Therefore f^-1(x) = (x - 3) / 4 Test: if x = 2, f(x) = 11 f^-1(11) = 2
18 Jan 2007 at 01:49 #4 Mackass Mackass Associate Joined 22 Jan 2005 Posts 1,196 Location West London Don't want to start a new thread. But basically, what is that symbol {x E R}? The topic is functions, anyone know?
Don't want to start a new thread. But basically, what is that symbol {x E R}? The topic is functions, anyone know?
18 Jan 2007 at 01:58 #5 Jotun Jotun Soldato Joined 11 Jun 2005 Posts 3,606 Location Liverpool Mackass said: Don't want to start a new thread. But basically, what is that symbol {x E R}? The topic is functions, anyone know? Click to expand... I believe it means x is all real numbers.
Mackass said: Don't want to start a new thread. But basically, what is that symbol {x E R}? The topic is functions, anyone know? Click to expand... I believe it means x is all real numbers.
18 Jan 2007 at 02:00 #6 Mackass Mackass Associate Joined 22 Jan 2005 Posts 1,196 Location West London Jotun said: I believe it means x is all real numbers. Click to expand... Ah right, I get it now, cheers.
Jotun said: I believe it means x is all real numbers. Click to expand... Ah right, I get it now, cheers.
18 Jan 2007 at 02:03 #7 titaniumx3 titaniumx3 Soldato Joined 11 May 2006 Posts 5,786 the 'e' symbols should be read as 'element of'.