Help with a simulation.....

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29 Jan 2008
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217
Need some help guys....

A box moves down a conveyor belt 500 units in 3.3 seconds.

I have to simulate the movement of the rollers on the conveyor belt to the speed of the box. If they spin for 3.3 seconds how many degrees per second will they rotate? They have a diameter of 80 units.
 
Firstly you need to calculate how many units one rotation will traverse. Next, calculate how much rotation is required to achieve 500 units of movement. You now need to change the total rotation over the 3.3 seconds to find how much rotation occurs in 1 second.
 
the rollers have a circumference of 251.3 units (based on pi x D ie 80 x 3.142) so need to do 1.9896 (or 716.3 degrees) rotations to get the box from A to B if they are spinning for 3.3 seconds only then they need to travel 716.3/3.3 which = 217 degrees a second.

Or i'm an idiot :)
 
the rollers have a circumference of 251.3 units (based on pi x D ie 80 x 3.142) so need to do 1.9896 (or 716.3 degrees) rotations to get the box from A to B if they are spinning for 3.3 seconds only then they need to travel 716.3/3.3 which = 217 degrees a second.

Or i'm an idiot :)

:(
 
the rollers have a circumference of 251.3 units (based on pi x D ie 80 x 3.142) so need to do 1.9896 (or 716.3 degrees) rotations to get the box from A to B if they are spinning for 3.3 seconds only then they need to travel 716.3/3.3 which = 217 degrees a second.

Or i'm an idiot :)


Thanks LOAM
 
Does that make sence to you, it does to me but would hate for you to be wrong on my account
 
What do you mean by simulation?

I'm imagining two cyclinders, both driven, with a flat sticky belt between them.
If so you want distance / circumferance = number of rotations, i.e. 6.25/pi = number of rotations.

It rotates this many times in 3.3 seconds, so revolutions per second = (6.25/pi)/3.3

If you want it in degrees, multiply that by 360. If you want it in radians per second, it's 125/33 exactly.

If you wish to factor in slip between cyclinder and belt, say a coefficient of 0.9, that means the cyclinder has to turn further than it normally would, and so you do the same as above but taking the initial value the box has to move as (500/0.9) instead.

Simulation is a weird decription though, so I'm not sure I've got the right idea here.
 
What do you mean by simulation?

I'm imagining two cyclinders, both driven, with a flat sticky belt between them.
If so you want distance / circumferance = number of rotations, i.e. 6.25/pi = number of rotations.

It rotates this many times in 3.3 seconds, so revolutions per second = (6.25/pi)/3.3

If you want it in degrees, multiply that by 360. If you want it in radians per second, it's 125/33 exactly.

If you wish to factor in slip between cyclinder and belt, say a coefficient of 0.9, that means the cyclinder has to turn further than it normally would, and so you do the same as above but taking the initial value the box has to move as (500/0.9) instead.

Simulation is a weird decription though, so I'm not sure I've got the right idea here.


Hurrah, gives the same result as mine did @ 217 degrees a second, I hereby declare I am today's forum genius (even though this was yesterday :P)
 
Need some help guys....

A box moves down a conveyor belt 500 units in 3.3 seconds.

I have to simulate the movement of the rollers on the conveyor belt to the speed of the box. If they spin for 3.3 seconds how many degrees per second will they rotate? They have a diameter of 80 units.

I'm not sure you have explained the problem correctly. Spinning for 3.3s will not determine the degrees per second they rotate. Put another way - 70mph for 10s is the same as 70mph for 1s.

In order to move a belt at 500 units in 3.3s the belt must move at 500/3.3 units per second = 151.52 (to 2dp)

A roller with a diameter of 80 units will move the belt (assuming no slippage) 80*pi units per revolution = 251.28 units.

So to move 151.52 units in a second it will need 151.52/251.28 revolutions per second = 0.60 rpm = .60*360 degrees per second = 217 degrees per second.
 
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