Horse's horse power?

If you're talking about the horse pulling the guy's arms off you don't want power or torque. You want force.

Force (in Newtons) = Mass (in kg) * Acceleration (in meters per second)

A large horse like a Clydesdale might have a mass of 800 kg (remember that mass is in kg, weight is in N). If he is capable of accelerating at .5 m/s (not all that tough without a load), he'd have a force.

F = 800 kg * 2 m/s = 1600 N

That's about 2.5 times the force of gravity on a 72 kg man. The horse is capable of going much faster and is capable of being much heavier.
 
Gilly said:
A true wise man knows the extent of his knowledge.

I'm not all that knowledgable. More talented, really.
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modest, too! you'd better not let me down this weekend, i'm expecting an unrelenting onslaught of weird movement on the dancefloor! (whilst i watch from afar, as i'm scared of dancing :p)
 
Scuzi said:
A measurement in lb/ft probably wouldn't work as horses have hooves and not feet.
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Post. Of. The. Year.

DaveyD said:
Torque's the not the right measurement, as it's not rotating....

I'd have thought the maximum force the horse can pull in Newtons is what you'd need...
"lb / ft" is a measurement of pressure Scuzi, "lb ft" is torque :p



ft lb / minute, not ft/lb /minute :p
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lb/ft^2, no?

Or N/m^2...

*n
 
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