how does a computer work out a hexadecimal sum

Narj · 15 Mar 2012 at 14:58

youdsy said:
a computer has 26 address lines. calculate teh total memory capacity available in Mb

2^26 = 67108864 bits

1 Mbit = 1048576 bits, so

8Mbits ? (so 1 MegaByte...?)

I think that's right... I'm a bit rusty! Jeebus :/

D.P. · 15 Mar 2012 at 14:59

Tikkabhuna said:
Of course it takes Hex. You don't type a hex number in as binary do you?

My keyboard only has 2 buttons

edscdk · 15 Mar 2012 at 15:01

Tikkabhuna said:
Of course it takes Hex. You don't type a hex number in as binary do you?

I assume that is a joke....

you press the 4 key and a series of 1's and 0's of produced... you press the A key and a different series of 1's and 0's is produced

bitslice · 15 Mar 2012 at 15:59

youdsy said:
got some other questions

describe two common types of micro controller architecture

Von Neumann architecture
Harvard architecture
modified Harvard architecture

Look up, copy n paste, get an A in computing GCSE

ZombieFan · 15 Mar 2012 at 16:06

bitslice said:
Von Neumann architecture
Harvard architecture
modified Harvard architecture

Look up, copy n paste, get an A in computing GCSE

I think the more traditional answer is RISC and CISC. Or it was back in the day when I was taught stuff.

TehBluebear · 15 Mar 2012 at 16:07

The lowercase H is just to signify that it's a hex number, and not decimal or otherwise.

Mason- · 15 Mar 2012 at 16:09

ZombieFan said:
I think the more traditional answer is RISC and CISC. Or it was back in the day when I was taught stuff.

Was taught at A-Level this

.

Also 4 bits of binary to a single hexadecimal digit if you didn't know.

youdsy · 15 Mar 2012 at 16:12

bitslice said:
Von Neumann architecture
Harvard architecture
modified Harvard architecture

Look up, copy n paste, get an A in computing GCSE

thanks

got an exam at 5 im doing HNC instrumentation engineering, not GCSE.

Energizer Bunny · 15 Mar 2012 at 16:13

bitslice said:
mov a,08h
mov b,02h
add a,b

You have sunk my battleship!

bitslice · 15 Mar 2012 at 16:25

ZombieFan said:
I think the more traditional answer is RISC and CISC. Or it was back in the day when I was taught stuff.

I wondered that myself, but since only two were asked for and there are a million variations of CISC/RISC, then I went for what sounded more like "architecture" to me. Changing an instruction set or adding pipelines isn't really doing anything other than making it efficient for an application.

As someone mentioned in a similar thread, the correct answer is what the teacher wants and bears no relation to reality