How to set order in which programs start on bootup

thecremeegg · 8 May 2010 at 18:34

I have 2 programs that I want to run on startup, but one has to run before the other else it errors. Is there a way I can do this?

Cheers

Greenlizard0 · 8 May 2010 at 18:57

Hmm, you may be able to write a batch file that does this. Then put a shortcut to it in the Startup folder.

thecremeegg · 8 May 2010 at 19:21

Greenlizard0 said:
Hmm, you may be able to write a batch file that does this. Then put a shortcut to it in the Startup folder.

I think you need to reword that, as there is not a chance that I can write a batch file

Ascendancy · 8 May 2010 at 19:23

Yeah, a batch file is what you're after.

UKDTweak · 8 May 2010 at 19:27

a batch file is the way to go...
Just create a new .txt file.. Then rename with .bat.
Now open the .bat in notepad and add the commands to run each program in the order you want them to run.

Ascendancy · 8 May 2010 at 19:32

Something like this will work:

Code:

@echo off

start c:\program1.exe
CHOICE /C:AB /D:A /T:10 > NUL
start c:\program2.exe

The choice command will pause the batch file for 10 seconds, you can adjust the pause by editing the /T:10 switch to the number of seconds you want.

Stick that into notepad and save as "wait.bat" or something and stick it in your startup folder.

Greenlizard0 · 8 May 2010 at 19:35

Code:

@ECHO OFF

START /min C:/1st program
TYPE NUL | CHOICE.COM /N /CY /TY,20 >NUL
START /min C:/2nd program

That will delay the second one for twenty seconds, hopefully this will allow the first to complete. Write it to a notepad file and save it as a batch file. Then stick it in your Windows' Startup folder.

Edit - beaten lol.

thecremeegg · 8 May 2010 at 20:02

Cheers guys, I'll give that a go!