31 Oct 2006 at 13:34 #1 demon8991 demon8991 Soldato Joined 7 Jan 2003 Posts 4,458 Location Gold Coast, Australia What is cosh(2x) written exponentially?
31 Oct 2006 at 13:48 #2 grahamjenks grahamjenks Associate Joined 8 Oct 2005 Posts 604 I think its (e^2x+e^-2x)/2
31 Oct 2006 at 14:18 #3 demon8991 demon8991 Soldato OP Joined 7 Jan 2003 Posts 4,458 Location Gold Coast, Australia Yer im trying to construct a proof, just need to maek sure both sides equal each other, i know im close just need to know for sure what cosh(2X) is.
Yer im trying to construct a proof, just need to maek sure both sides equal each other, i know im close just need to know for sure what cosh(2X) is.
31 Oct 2006 at 14:32 #4 grahamjenks grahamjenks Associate Joined 8 Oct 2005 Posts 604 Well a long winded way of showing this is: cosh(x) = (e^x + e^-x)/2 cosh(2x) = 1 + 2sinh(^2)x sinh(x) = (e^x - e^-x)/2 cosh(2x) = 1 + 2((e^x - e^-x)/2)^2 cosh(2x) = 1+ 2 ((e(2x) - 2 + e(-2x))/4) cosh(2x) = (e(2x) + e(-2x))/2
Well a long winded way of showing this is: cosh(x) = (e^x + e^-x)/2 cosh(2x) = 1 + 2sinh(^2)x sinh(x) = (e^x - e^-x)/2 cosh(2x) = 1 + 2((e^x - e^-x)/2)^2 cosh(2x) = 1+ 2 ((e(2x) - 2 + e(-2x))/4) cosh(2x) = (e(2x) + e(-2x))/2
31 Oct 2006 at 14:44 #5 demon8991 demon8991 Soldato OP Joined 7 Jan 2003 Posts 4,458 Location Gold Coast, Australia Ahhh brilliant thats what i hoped it would be, thanks mate. Proof has worked!!!