Java help.

Energize · 18 Mar 2009 at 15:37

Keeps saying it can't find the variable "phone1", but it's decleared right above it!?

Code:

import GSMNetwork.*;

public class send {	
	public static void main(String[] args) {
		try {
			MobilePhone phone1 = new MobilePhone("0123456789");
		} catch (NetworkNotAvailableException nna) {
			System.out.println("Network not available!");
			System.exit(1);
		}
		TextMessage txt = new TextMessage("Hi");
		phone1.sendMessage(txt, "9876543210");
	}
}

Dj_Jestar · 18 Mar 2009 at 15:48

Code:

import GSMNetwork.*;

public class send {	
	public static void main(String[] args) {
		MobilePhone phone1;
		try {
			phone1 = new MobilePhone("0123456789");
		} catch (NetworkNotAvailableException nna) {
			System.out.println("Network not available!");
			System.exit(1);
		}
		TextMessage txt = new TextMessage("Hi");
		phone1.sendMessage(txt, "9876543210");
	}
}

Energize · 18 Mar 2009 at 16:08

I tried that earlier, but then I get, "phone1 might not have been initialised" and "unreported exception: phonenotinserviceexception, must be caught or declared to be thrown".

PaulStat · 18 Mar 2009 at 16:19

Energize said:
I tried that earlier, but then I get, "phone1 might not have been initialised" and "unreported exception: phonenotinserviceexception, must be caught or declared to be thrown".

Have you tried having it as an instance variable instead of a local variable

Or you could do as DJ_Jestar says but have it as MobilePhone phone1 = null; instead

As for the exception, not knowing anything about GSM API it's hard to tell, but I'm guessing phone1.sendMessage could throw a PhoneNotInServiceException

Dj_Jestar · 18 Mar 2009 at 16:32

this might clear that error..

Code:

import GSMNetwork.*;

public class send {	
	public static void main(String[] args) {
		MobilePhone phone1;
		try {
			phone1 = new MobilePhone("0123456789");
		} catch (NetworkNotAvailableException nna) {
			System.out.println("Network not available!");
			System.exit(1);
			return;
		}
		TextMessage txt = new TextMessage("Hi");
		phone1.sendMessage(txt, "9876543210");
	}
}

Energize · 18 Mar 2009 at 16:44

Fixes the initialisation error

. The other error was caused the sendMessage method, fixed that now.

PaulStat · 18 Mar 2009 at 16:46

Energize said:
Fixes the initialisation error , still got the undecleared exception problem though.

I reckon the fix for that one will probably be

Code:

try {
   phone1.sendMessage(txt, "9876543210");
} catch(PhoneNotInServiceException e) {}

Energize · 18 Mar 2009 at 16:48

PaulStat said:
I reckon the fix for that one will probably be

Code:

try { phone1.sendMessage(txt, "9876543210"); } catch(PhoneNotInServiceException e) {}

Heh, just worked it out before you posted.

PaulStat · 19 Mar 2009 at 09:12

Energize said:
Heh, just worked it out before you posted.

well I did mention it back in post #4