Logic Puzzles

Martynt74

Martynt74

Martynt74

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Joined
20 Feb 2004
Posts
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Hondon de las Nieves, Spain
Just been doing an online job assessment and whilst it was a lot tougher than previous ones i've had to do in the numerical sections, i found some of the logic puzzles bloody impossible.

Figured i'd post them here and see what people thought were the answers. I'm fairly sure i guessed!

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I would have gone with the two 'circular' dots for the top one (top row third from right), and I probably would have guessed the second one as I've sat here for a minute without any confidence.

Not worth wasting time on these tests it there are more questions to follow - better off cutting your losses and going to the next one :p
 
First one is easy second one I'd have passed and hoped to have time at the end to go back (assuming it was timed)(probably would have passed a second time :D).
 
Quite annoying now. I can easily see the first one now as you see it's pretty straightforward but in the pressure of the test i think i was flustered by failing at previous questions (15 in total)

No option to go back and there were 60 seconds per question. It was the 3rd test after 30 mins of numerical and written assessments so think i probably should've given myself a break before flying straight into it.
 
Ahh ok I would have had guess in that case.

I do enjoy these sort of questions mainly because I don't understand a lot of them.
 
Alright lads, gather 'round.

A prison island with 100 inmates exists. The foreman - sick of seeing their ugly faces - greets the inmates one day with a proposition. "I have set up a single room, with a light bulb and light switch inside. The light will start OFF. I will place you all in solitary confinement, and call you at random into the room. If one of you can be 100% certain that every single inmate has visited this room, I will set you all free. If you're wrong, I will shoot you all in the back of the head." The inmates group up to form a strategy, and then proceed to be placed in solitary confinement.

...what is the strategy?
 
Assuming there's no limit to time, then I'd hazard a guess at one person being a counter once a prisoner enters the room and finds the light off they turn it on(only the first time they visit) the counter classes that as one person and turns it back off until they hit 99.

Quick edit: nope I'm full of **** that wouldn't account for more than one person being in there before the counter is summoned again. I don't know :(.

Maybe run the above process and once the counter has gone a few weeks without turning the light off assume everyone has been?

What do you care if you get it wrong everyone will be too dead to hold it against you :D.

Edit2: Also will the bulb be tested if working? Dead bulb would quickly end my idea :D.

Edit3: Is there an actual answer?
 
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Umm, on their first visit to the room they could each unscrew the bulb and use the base to scratch a line on to the wall or something like that, before replacing it back into the socket? So it wouldn't matter if there were any repeat visits and someone would eventually be there making the 100th line.
 
Nullvoid said:
Umm, on their first visit to the room they could each unscrew the bulb and use the base to scratch a line on to the wall or something like that, before replacing it back into the socket? So it wouldn't matter if there were any repeat visits and someone would eventually be there making the 100th line.
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Good idea.


We need more rules on this puzzle is wall scratching allowed?
 
The prisoners need to select a boss who's job it is to turn the light on and decide when everyone has been in the room. All other prisoners must only ever turn it off or leave it alone.

If a prisoner enters the room to find the light off they must leave it alone. The first time a prisoner enters the room and finds it on they must turn it off. The second time a prisoner enters the room and find the light on they must leave the light alone.

The boss knows that he will have to turn the light on once for every time a prisoner turns it off plus once because the bulb was off in the first place. If the boss counts the number of times they turn the light on then they can be sure that once they have turned it on 100 times then each prisoner has been in the room at least once.

I think I remember this from my higher maths days?
 
Salsa said:
The prisoners need to select a boss who's job it is to turn the light on and decide when everyone has been in the room. All other prisoners must only ever turn it off or leave it alone.

If a prisoner enters the room to find the light off they must leave it alone. The first time a prisoner enters the room and finds it on they must turn it off. The second time a prisoner enters the room and find the light on they must leave the light alone.

The boss knows that he will have to turn the light on once for every time a prisoner turns it off plus once because the bulb was off in the first place. If the boss counts the number of times they turn the light on then they can be sure that once they have turned it on 100 times then each prisoner has been in the room at least once.

I think I remember this from my higher maths days?
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Doesn't that fall short of my "fall short of more than one prisoner turning up before the boss" edit?

edit: My brain is all over the place. No it wouldn't they'd just have to wait longer to make sure each prisoners appearance had been counted. Guess I was right then talked myself out of it :D. There is still a broken bulb issue :D.
 
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I think it's 2 dots for the top one due to the fact there is a tile of 1, 2 and 3 symbols in each row and the dots fits the overall pattern, and 3 left pointing arrows for the bottom one due to the number of each symbol in each row.
 
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