Maths Help

Django x2 · 23 Oct 2008 at 01:00

If I have

K = X^2 over C

and then Log it, why does it become

K = log X^2 - logC

Thanks

ugatennis08 · 23 Oct 2008 at 01:02

Yes, assuming the have the same base.
or

2logx - log c =K

Django x2 · 23 Oct 2008 at 01:05

ok, but why. Why is it not log X^2 over logC?

Ricochet J · 23 Oct 2008 at 01:06

Lucero said:
If I have

K = X^2 over C

and then Log it, why does it become

K = log X^2 - logC

Thanks

Log rules

Log(x/y) = logx - logy

Edit: I recommend you get some sleep, attempt the questions in the morning after rereading logarithm rules.

ugatennis08 · 23 Oct 2008 at 01:07

It's just an identity

log(xy) = Logx + logy
Log(x/y) = Logx - logy
log(x^2) = 2logx

Django x2 · 23 Oct 2008 at 01:08

ah yes, of course. Thanks

acccc · 23 Oct 2008 at 01:12

daym, i wish i knew what the hell you guys were talking about. sounds epic. o_O

Dunks · 23 Oct 2008 at 01:13

It's pretty simple stuff