Maths homework help please :)

Mason-

Mason-

Mason-

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Yay A-Level maths. -.-

Okay got the following hyperbolic trig equation to solve:

Solve the equation 2tanh^2(x) - sech(x) = 1, giving your answer(s) in logarithmic form.
I started off by multiplying through by cosh^2(x) to get:

2sinh^2(x) - cosh(x) = cosh^2(x)

Then

2(1 - cosh^2(x)) - cosh(x) = cosh^2(x)

2 - 2cosh^2(x) - cosh(x) = cosh^2(x)
3cosh^2(x) + cosh(x) = 2

Then using identities cosh(x) = 0.5(e^x + e^-x)

I got it down to
something which worked out completely wrong =/

Maybe I should have converted to the exponential form right at the start,

any pointers?

thanks.
 
Last edited:
i wonder what the worlds crippled economy, and starving children in africa think of your little equations. yeeeehaaaw

catch you on the flip
 
Modular said:
i wonder what the worlds crippled economy, and starving children in africa think of your little equations. yeeeehaaaw

catch you on the flip
Click to expand...

I wonder what they think of your post :P

Either way I have to do it if I want to go to university, which coincidentally I do.
 
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