which would tell you its size, not its weight, you're fired.
What, this would work. Everyone knows the density of an elephant off the top of their head
which would tell you its size, not its weight, you're fired.
“How many basketballs can you fit in this room?”
calculate the volume of the room by measuring the length, width and breadth. A basketball is 29.5 inches in circumference, which gives it a volume of about 435 cubic inches.
Suppose the room is 12' x 12' x 8'. That gives it a volume of 1,990,656 cubic inches. Now, if spheres filled a room with perfect efficiency (i.e. no air gaps between them), there would be 1,990,656/435 = 4756.22 i.e. 4756 basketballs in the room.
Now, spheres don't pack together perfectly efficiently. The most efficient packing arragement is where you have staggered layers. This has a density of Pi/(2*sqrt(3)). Multiplying this by our original amount gives us 4150 basketballs in a room 12' x 12' x 8'.
Can get a lot more than that in the room if the basketballs are deflated first.
For the elephant one I would throw it in a swimming pool and work out the displacement.
which would tell you its size, not its weight, you're fired.
Not quiteAbsolutely nothing.
The implication is that the water level would rise slightly due the volume of the brick, but the boat would now displace less water now that the brick is no longer on board, thus the effects cancel each other out, and there is no net effect to the water level.
which would tell you its size, not its weight, you're fired.
Don't be ridiculous, it'd tell you the mass of the elephant. The volume of water displaced is not equal to the volume of whatever's doing the displacing, unless external force is used to fully submerge the object - it's a product of mass.
No, water weighed, unless you know the density of an elephant it is useless.And 1 litre of water is approximately 1 kg, therefore elephant weighed![]()
What, this would work. Everyone knows the density of an elephant off the top of their head
I don't think it would float, I get the impression elephants are pretty dense.The elephant will displace it's own weight in water, assuming it floats. Start with a tank full to the brim, put elephant in and then take it out and measure the drop in water level, that plus surface area of the tank then tells you the volume and hence weight of water displaced.
Have I woken up yet?
No, so long as what you're putting in the water is denser than water, the water displaced will be the same volume as what you've put in. How could it possible be anything else?
The elephant will displace it's own weight in water, assuming it floats. Start with a tank full to the brim, put elephant in and then take it out and measure the drop in water level, that plus surface area of the tank then tells you the volume and hence weight of water displaced.
Have I woken up yet?
No, so long as what you're putting in the water is denser than water, the water displaced will be the same volume as what you've put in. How could it possible be anything else?
A manhole cover is round because the manhole is round.
elephants float though don't they?![]()
Not quite![]()
And 1 litre of water is approximately 1 kg, therefore elephant weighed![]()
elephants float though don't they?![]()
The elephant will displace it's own weight in water, assuming it floats. Start with a tank full to the brim, put elephant in and then take it out and measure the drop in water level, that plus surface area of the tank then tells you the volume and hence weight of water displaced.
Have I woken up yet?