Quick math question

Soldato
Joined
18 Jul 2006
Posts
5,704
Location
Geneva
If somebody could help me with this question I would be most appreciative


Edit wrong clipboard.

A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started
the same course and cycled at an average speed of 11 mph. How long after the jogger started did the
cyclist overtake the jogger?
 
Associate
Joined
2 Apr 2007
Posts
291
Killa_ken said:
If somebody could help me with this question I would be most appreciative


Edit wrong clipboard.

A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started
the same course and cycled at an average speed of 11 mph. How long after the jogger started did the
cyclist overtake the jogger?

In one hour, the first jogger is 4 miles ahead. If the first is moving at 4mph and the second at 11mph, the gap is closing at a rate of 7mph. Therefore, 4 miles distance between the two divided by the rate of closure (7mph) is the time taken.


34 minutes 17 seconds.

[Edit] - 1 hour 34 minutes, time starts when the jogger started moving.
 
Back
Top Bottom