# Quick math question

#### Killa_ken

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If somebody could help me with this question I would be most appreciative

Edit wrong clipboard.

A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started
the same course and cycled at an average speed of 11 mph. How long after the jogger started did the
cyclist overtake the jogger?

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#### benktlottie

Permabanned
Great pic ! Who is she ????

#### Killa_ken

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OP
Sorry had something else on my clipboard

#### Dunks

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Killa_ken said:
Sorry had something else on my clipboard
I noticed

#### starscream

Permabanned
I would differentiate her right angles.

Associate
21.8 minutes.

#### supernova9

Associate
Killa_ken said:
If somebody could help me with this question I would be most appreciative

Edit wrong clipboard.

A jogger started a course and jogged at an average speed of 4 mph. One hour later, a cyclist started
the same course and cycled at an average speed of 11 mph. How long after the jogger started did the
cyclist overtake the jogger?

In one hour, the first jogger is 4 miles ahead. If the first is moving at 4mph and the second at 11mph, the gap is closing at a rate of 7mph. Therefore, 4 miles distance between the two divided by the rate of closure (7mph) is the time taken.

34 minutes 17 seconds.

 - 1 hour 34 minutes, time starts when the jogger started moving.

#### benktlottie

Permabanned
I prefered the woman...
Anyway, at a guess 25 minutes later, maybe 30

#### Killa_ken

Soldato
OP
1.57 is correct thanks guys!

Man of Honour
Maths

#### supernova9

Associate
Wooo, I win!! What's my prize?

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#### Vonhelmet

Caporegime
4 + 4x = 11x will give you the time as x.

4 = 7x

x = 34 minutes (roughly)