Quick maths problem

pinkacidbootson · 28 Oct 2007 at 20:20

Just a quick one:

(xyz)^3 / x(yz)^2

The answer to this problem is worth several internets.

[TR]SweetSpotOz · 28 Oct 2007 at 20:30

(xyz)(xyz)(xyz)

that is just x*x*x*y*y*y*z*z*z surely so I'm sure you can do the rest yourself.

The solution I've got to that is x^2yz

csmager · 28 Oct 2007 at 20:33

yzx^2, I'd've thought.

[TR]SweetSpotOz · 28 Oct 2007 at 20:34

csmager said:
Solution.

"Let the boy earn his spurs" etc etc

pinkacidbootson · 28 Oct 2007 at 20:43

markyp23 said:
(xyz)(xyz)(xyz)

that is just x*x*x*y*y*y*z*z*z surely so I'm sure you can do the rest yourself.

The solution I've got to that is x^2yz

Could have had a shocker though.

Sweet tapdancing christ, I think you're onto something. I'm kicking myself for not remembering that

[TR]SweetSpotOz · 28 Oct 2007 at 20:54

simon50 said:
Sweet tapdancing christ, I think you're onto something. I'm kicking myself for not remembering that

It's a very confusing layout but one you notice the brackets are telling you to do (xyz)^3 = (xyz)*(xyz)*(xyz) = x*y*z*x*y*z*x*y*z it's easy pickings!

csmager · 28 Oct 2007 at 21:02

They are serving a purpose - xyz^3 is quite different to (xyz)^3

PurpleDinosaur · 28 Oct 2007 at 21:11

markyp23 said:
It's a very confusing layout but one you notice the brackets on the numerator aren't serving any purpose it's easy pickings

You're trying to say that (xyz)^3 is the same as xyz^3?

OP, disregard anything markyp has said.

EDIT: Actually, he got the right solution, not sure how if he ignored the brackets though.

[TR]SweetSpotOz · 28 Oct 2007 at 21:20