Simple PHP If Statements - Help

Soldato
Joined
31 Oct 2005
Posts
8,845
Location
Leeds
Hello there again, I've left you alone for a while and only have a quick question this time

I currently have a piece of code that finds the number of a user, and kicks out their picture from file, only problem is, if there isn't a picture, it displays an error message.

Put simply, I'm after something like, "if $file <0 then display somefile.jpg"

Should be a 5 second job for some on you, would be much apperciated

Here's the PHP

PHP:
<?php  
foreach (glob("$d_no.*") as $file) {
echo '<td>' . "<a href='$file' target=_blank><img  src='$file'  alt='$file'  width='180' height='300'></a>" . '</td>'; 
}   
echo '</table>'; 

?>
 
But if no files match the pattern then the for loop wont even execute once will it? You might need to store it in an array first, something like this:


I haven't used glob before so don't know if this will work!

Cheers for the PHP attempt, I tried
PHP:
<?php  
$files = glob("$d_no.*");
if(sizeof($files) > 0) {
 // There are some files
 foreach ($files as $file) {
echo '<td>' . "<a href='$file' target=_blank><img  src='$file'  alt='$file'  width='180' height='300'></a>" . '</td>'; 
}   
} else {
echo '<td>' . "<a href='/test.jpg' target=_blank><img  src='$file'  alt='$file'  width='180' height='300'></a>" . '</td>'; 
echo'</table>';
// Do something else
}

echo '</table>'; 

?>

Which works fine on users with pics, but alas the same error without

Warning: Invalid argument supplied for foreach()
 
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