Teaching my self electronics and require knowledgable mind

[sid]

The easiest way to visualise it is think of a garden hose. The tap is voltage, the water flow in the hose is current and you standing on the hose is resistance.

If you turn the tap on full, you get loads of current flow if there isnt any resistance. If you then stand on the pipe, you get loads of resistance and therefore the current (water through the pipe) reduces. If you turn the tap down the voltage reduces as does the current capability.

Excellent analogy

 

[MikeHunt79]

That would depend on what you are soldering, there are plenty of surface mount components that could potentially be damaged due to excessive heat if you used silver solder. Silver solder is completely un-necessary so I wouldnt bother using it.

So silver solder must have a higher melting point also? SMD's are a pita tbh, even with leaded normal solder I can't really solder them... Hole mount all the way for me. :/

 

[Kanifee]

looking for some clarification on resistor dividers, took me a while to understand the math behind them as the book didnt explain it propery it was just giving me Vout=R1/(RA+RB). It wasnt untill i found a site explaining it as Vout=R1/(RA+RB)xVin it was the fact they didnt say it had to be multiplyed by the origanel voltage into RA, this aside i done a few quiz's got the values right so im pretty sure i understand the equation to find the answer now its just understanding why the circuit works that way, and i dont really want to move on untill i grasp it properly.

in the picture i have tried to explain what im having difficuilt to understand, i know by the method i learnt that Vout is 5v, what i dont understan is why that resistor effects the outcome, hope im making sense hear.

 

[Psycrow]

Think of it in terms of water again. Resisters block the flow (current), this blockage causes pressure to build up (voltage). The bigger the blocking force, the higher the pressure buildup over that resister. The total buildup can't be higher than the input pressure (Vin). So from your picture you have 15V of input voltage, the larger resister causes the greatest volt drop and using the formula you mentioned, this means 10V for Ra and 5V for Rb.
As for bypassing Ra, I'm not quite sure what you mean. The current has to go from the +v of Vin -> through Ra -> Through Rb - > back to -ve of Vin.

If you connected directly from +ve Vin -> Rb -> -Ve Vin the voltage Vout would be 15V.

Also, you added my GF to msn by accident, her email address was in my trust. All sorted now