Trigonometry help please..

Caporegime
Joined
18 Oct 2002
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Back in East London
I have a vector. I know it's start point, the distance, and it's angle. How to I find out what the end point is on the grid?

e.g. the line starts at x: 23, y: 25, is 100 units long and the angle is 72 degrees.

It's been so long since I did anything more complicated than working out what change I'll get from a note, that I've completely forgotten :( p.s. I'll also need to calculate fixed points along the line.. if that will make any difference?
 
You can use sinθ = o/h for the first step. Where θ = 72° and h = 100.

The rest should be self explanatory.

Hope that helps :)
 
Jonny ///M said:
Well its velocity.....ah **** knows it still has to accelerate....against the force of jesus.

Too much thinking....im going to bed. :(

Once i finish my cheerios

they accelerate vertically due to mavity, but if you neglect frictional forces, there's no forces acting horizontally once it's in the air.
 
Rebelius said:
they accelerate vertically due to mavity, but if you neglect frictional forces, there's no forces acting horizontally once it's in the air.

How can it accelerat with mavity? mavity is pulling it down.....after it hits the peak of the curve thing...im :confused: ....bed :(
 
What do you mean by accelerate? Isn't an acceleration a change in velocity. If it's not moving then it lifts off it'll accelerate both upwards and horizontally as it gets faster and faster (assuming it's not going perfectly at right angles to the Earth)?
 
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