Using a variable as a function name (php)

[Wimnat]

I'm 99% sure this is possible because I think I've done it before but I can't remember how.

I have this line...

$avrStatArray[$i] = db_getXXXAvr($row["Call-ID"]);

I want to replace 'XXX' with $var

A little help...

 

[Wimnat]

Sorted...

$var = 'db_get . $x . Avr';

$avrStatArray[$i] = $var($row["Call-ID"]);

 

[meghatronic]

Can't you just concant, as per your original:

$avrStatArray[$i] = 'db_get . $x . Avr' . ($row["Call-ID"]);

 

[Wimnat]

Can't you just concant, as per your original:

$avrStatArray[$i] = 'db_get . $x . Avr' . ($row["Call-ID"]);

Possibly. I didn't try. I need to pass the variable to another function anyway.

 

[Jaffa_Cake]

Can't you just concant, as per your original:

$avrStatArray[$i] = 'db_get . $x . Avr' . ($row["Call-ID"]);

Tried that and it didn't work for me. Tried several different methods and only Wimnat's worked.