Venn Diagram

Soldato
Joined
29 Jul 2004
Posts
6,710
Location
Esher
Hi All,

I've just had a phone call from my aunt and she's having trouble with my cousins homework.

I cannot figure it out :( Damn GCSE's

If a total of 40 people have seen Harry Potter on either DVD, Cinema, Video or a combination of them.

Video 23
DVD 22
Cinema 17
Video and DVD 12
Video and Cinema 6
DVD and Cinema 7

How many people have watched Harry Potter on all Video, DVD and Cinema?

The answer is probably obvious but I cannot figure it out at all!

So if anyone knows, please let me know!
 
I think the answer is three.
I haven't done Venn diagrams for many ears and that is purely an educated guess.

EDIT: Scrap that I have even less of an idea than I thought!
 
Last edited:
Hi All,

I've just had a phone call from my aunt and she's having trouble with my cousins homework.

I cannot figure it out :( Damn GCSE's

If a total of 40 people have seen Harry Potter on either DVD, Cinema, Video or a combination of them.

Video 23
DVD 22
Cinema 17
Video and DVD 12
Video and Cinema 6
DVD and Cinema 7

How many people have watched Harry Potter on all Video, DVD and Cinema?

The answer is probably obvious but I cannot figure it out at all!

So if anyone knows, please let me know!
3, you need to know how many arent any of the 3
 
Last edited:
GCSEs are supposed to be educating students. I see videos and DVDs as miseducation as they are both videos essentially. The question on the paper should have listed VHS and DVD as the first 2 :-)

Same debate as "is it a PC or a laptop?"
 
GCSEs are supposed to be educating students. I see videos and DVDs as miseducation as they are both videos essentially. The question on the paper should have listed VHS and DVD as the first 2 :-)

Same debate as "is it a PC or a laptop?"

Would kids around GCSE age know what VHS is?
 
k22134.jpg
 
Use algebra to work it out. Say the value for all three is x. Draw the diagram and work backwards. So if Video and DVD is 12, do "12 - x", etc.

40 = x + 12 – x + 6 – x + 7 – x + 23 – (12-x) – x – (6-x) + 22 – (12-x) –x –(7-x) + 17 – (6-x) – x –(7-x)

40 = x + 37

x=3
 
I'm probably being a right tard chops, but in that diagram how do you know how many are exclusively in video?

23-12-6=5 sure, but isn't that 5 to be split between 'just video' and 'all 3'? Think I'm reading the question wrong.
 
I'm probably being a right tard chops, but in that diagram how do you know how many are exclusively in video?

23-12-6=5 sure, but isn't that 5 to be split between 'just video' and 'all 3'? Think I'm reading the question wrong.

I didn't say it was right...
 
Last edited:
Thinking about it for more than one minute I now think the question is impossible to answer. You need to solve the set equations:

V = 5 + x;
D = 3 + x;
C = 4 + x;

There can be multiple answers seeing as we only really fully know the intermediate steps.

What's confusing the problem is that the core options (V, D, C) have been compounded and we don't know if the compound includes the 'all (x)' option or not. I'm going to use some experience though and assume it's not this complicated as it's GCSEs and therefore my initial picture is the correct answer.
 
Last edited:
Thinking about it for more than one minute I now think the question is impossible to answer. You need to solve the set equations:

V = 5 + x;
D = 3 + x;
C = 4 + x;

There can be multiple answers seeing as we only really fully know the intermediate steps.

That's what I immediately thought. I just didn't want to look really stupid :p

I always reserve the right to look that way though :D
 
That's what I immediately thought. I just didn't want to look really stupid :p

I always reserve the right to look that way though :D

You can probably make it even more complicated by questioning whether the intermediate steps are also compounds of the 'all' option. Because of all this nonsense I am convinced my picture is correct. Occam's' razor and whatnot.
 
You can probably make it even more complicated by questioning whether the intermediate steps are also compounds of the 'all' option. Because of all this nonsense I am convinced my picture is correct. Occam's' razor and whatnot.

I take it from this comment that this is why there is a lack of colours in your diagram. Personally I would have chosen red, green and blue for the main circles and the RGB combination for the intersections.
 
Back
Top Bottom