Ive seen several accounts of e8*00 chips degrading above 1.45V, though I believe only on air.
Black's equation
MTTF mean time to failure, from electromigration specifically
j is the current density
T is the absolute temperature in K
w is the width of the metal wire
The other letters are constants found empirically for a given processor. So this will not tell you how long the chip will last, however it does show some relationships. Increases in current density will decrease lifespan, as current density increases with voltage, voltage will decrease lifespan.
W is the 45nm/32nm etc, decreasing this reduces time before failure. Hence 1.5V fine for a q6600 but a bit risky for a e8*00.
Note the exponential temperature dependence. This is the 'strongest' term in the equation which suggests heat is the biggest risk. Hence 1.7V under phase doesn't seem to matter all that much.
The only other thing I have to add is that at voltage V, the D0 stepping x58 i7 draws more current than the C0 stepping, so the D0 stepping chip will suffer more from excessive current than the C0. It may be negligible in both cases.
This doesn't tell you how hard a processor can be pushed though
Black's equation

MTTF mean time to failure, from electromigration specifically
j is the current density
T is the absolute temperature in K
w is the width of the metal wire
The other letters are constants found empirically for a given processor. So this will not tell you how long the chip will last, however it does show some relationships. Increases in current density will decrease lifespan, as current density increases with voltage, voltage will decrease lifespan.
W is the 45nm/32nm etc, decreasing this reduces time before failure. Hence 1.5V fine for a q6600 but a bit risky for a e8*00.
Note the exponential temperature dependence. This is the 'strongest' term in the equation which suggests heat is the biggest risk. Hence 1.7V under phase doesn't seem to matter all that much.
The only other thing I have to add is that at voltage V, the D0 stepping x58 i7 draws more current than the C0 stepping, so the D0 stepping chip will suffer more from excessive current than the C0. It may be negligible in both cases.
This doesn't tell you how hard a processor can be pushed though
