It's not /thread, it's not 1 which is simply wrong.
It's not /thread, it's not 1 which is simply wrong.
but scot googul/mai calculater/my mafs teecher/myself (who is never wrong) sed it is 9Just a message for some of those who are poking fun at others.
There are two solutions, differing in interpretation of the ambiguous expression.
If you can't understand this then refrain from accusing others of lacking intelligence. Any spastic can apply some Kindergarten mathematical operating rule without really having a grasp on the subject. The argument being put fourth by those who are qualified to debate this is that in practical application of mathematics either interpretation may be more appropriate given the context of the problem at hand, although the expression is still irrefutably ambiguous.
Just a message for some of those who are poking fun at others.
There are two solutions, differing in interpretation of the ambiguous expression.
If you can't understand this then refrain from accusing others of lacking intelligence. Any spastic can apply some Kindergarten mathematical operating rule without really having a grasp on the subject. The argument being put fourth by those who are qualified to debate this is that in practical application of mathematics either interpretation may be more appropriate given the context of the problem at hand, although the expression is still irrefutably ambiguous.
Only a sith deals in absolutes.
I can't believe I just said that. We both fail at life![]()
Completely depends if you interpret its as:
6÷2*(1+2)
or
6/2(1+2)
Personally i would go for the former as theyve used '÷' sign rather than fraction but its all done to interpretation so its hard to argue either is wrong
This is what my wife said, only she put it like this:
"It is just a silly poorly written equation designed to get you to argue about nothing all night on the internet.....forget about it and go to sleep!"
If you can't understand this then refrain from accusing others of lacking intelligence. Any spastic can apply some Kindergarten mathematical operating rule without really having a grasp on the subject. The argument being put fourth by those who are qualified to debate this is that in practical application of mathematics either interpretation may be more appropriate given the context of the problem at hand, although the expression is still irrefutably ambiguous.
Who believes that the 2 is a co-efficient of the brackets?
I wouldn't blame you for this because the question slips in and out of various maths notations.
It's just how to percieve and interpret it. Is it 6/2 being the coefficient of the bracket? Or is it suggesting 6/(2(1+2)), well, it's down to the person, and how they write their maths.
People have already said it's ambiguous.
Not to me, but then I'm arrogant and hate to admit I might be wrong. The original question uses ÷ rather than / so if the division were the coefficient it'd be written (6 ÷ 2)(1 + 2). Then it'd be indisputably 9. As it is, the original equation is written 6 ÷ 2(1 + 2), and it's pretty obvious that the coefficient is the 2 on its own. Converting it into a computer-friendly format sullies it - written out, the answer is 1. Anything else is just sloppy maths to be honest.
I was referring to the question. I know x^2=9 has 2 answers but in this case such as 2+2, there is only one answer and that is 5.