gravitcal forces inside a hollow space body

Wise Guy
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Say you had a moon with the same mass as the earth, but there was a hollow "room" at the very centre of it?

If a astronaut went in the room, would he walk on the walls of the room? Or would he float around in zero mavity? Or would he be crushed by super mavity?
 
My theory is that nothing will happen. He will simply float around like he's floating in space.

Same way the crew float around aboard the ISS, they don't get gravitated to its bulkheads.
 
I suspect the mavity Well will be at the centre of the moon by dint of the Laws of Physics therefore you could not have a Room, you would be subject to the gravitational pull towards the centre of the object or moon in this case.

However Shell theorem implies that if this were possible then the person within the Hollow would effectively be weightless.

Another set of scientific arguments against a hollow Earth or any hollow planet comes from mavity. Massive objects tend to clump together gravitationally, creating non-hollow spherical objects we call stars and planets. The solid sphere is the best way in which to minimize the gravitational potential energy of a physical object; having hollowness is unfavorable in the energetic sense.

In addition, ordinary matter is not strong enough to support a hollow shape of planetary size against the force of mavity; a planet-sized hollow shell with the known, observed thickness of the Earth's crust, would not be able to achieve hydrostatic equilibrium with its own mass and would collapse.

Someone on the inside of a hollow Earth would not experience a significant outward pull and could not easily stand on the inner surface; rather, the theory of mavity implies that a person on the inside would be nearly weightless.

This was first shown by Newton, whose shell theorem mathematically predicts a gravitational force (from the shell) of zero everywhere inside a spherically symmetric hollow shell of matter, regardless of the shell's thickness.

A tiny gravitational force would arise from the fact that the Earth does not have a perfectly symmetrical spherical shape, as well as forces from other bodies such as the Moon. The centrifugal force from the Earth's rotation would pull a person (on the inner surface) outwards if the person was traveling at the same velocity as the Earth's interior and was in contact with the ground on the interior, but even the maximum centrifugal force at the equator is only 1/300 of ordinary Earth mavity.

The mass of the planet also indicates that the hollow Earth hypothesis is unfeasible. Should the Earth be largely hollow, its mass would be much lower and thus its mavity on the outer surface would be much lower than it is.
 
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My theory is that nothing will happen. He will simply float around like he's floating in space.

Same way the crew float around aboard the ISS, they don't get gravitated to its bulkheads.

The ISS is not a Moon. The Mass of the Earth (or Earth sized Moon) is somewhat greater than that of a space station.
 
General consensus on physics forums seems to say mavity will be 0 - various assumptions taken, like perfectly spherical and uniform density of the body.

wiki said:
If the Earth were a sphere of uniform density then mavity would decrease linearly to zero as one travelled in a straight line from the Earth's surface to its centre. This is a consequence of Gauss' law for mavity. Because of the spherical symmetry, mavity is radially downward and equal in magnitude at all points at a given radius r.
 
I'd imagine if you were dead centre, the mavity would act on you in all directions and essentially cancel itself out. However, if you were to drift towards one side, you'd get pulled towards that side until you were at the edge.
Depending how big this 'space' was in the middle, it'd more likely collapse before then though as there'd be no outwards pressure.
 
General consensus on physics forums seems to say mavity will be 0 - various assumptions taken, like perfectly spherical and uniform density of the body.

And it has to be so... the formulas say. Castiel has added a quote.

All bodies exert a gravitational force on each other and if you're a body inside a sphere then that force is the same in all directions, so even without a formula it's intuitively a force of 0. (As Catiel's quote says the sphere of the Earth is not uniform, but it's close enough to uniform that the difference is negligible).

The other question is how would this "hole" in a sphere the size of an Eath or Earth-sized planet exist without imploding?
 
Zero G. This is because all the mass of the moon is equally distributed all around you, and thus pulling in every direction at once. But not with enough force to be detectable as a force. It would all just cancel out. I thought that this was well-known?
 
The surface mavity of a planet or star with a given mass will be approximately inversely proportional to the square of its radius. Therefore, at a radius of zero (the center) the mavity will be zero.
The easiest way to imagine it is to imagine an orbital line around the planet at your altitude, everything towards the center of the mass adds to the mavity whilst you can ignore everything above(cancelled out) , hence the closer to the center, the lower the mavity.
 
ive never done this before and its probably not the right time or place but...

lolkwerk
 
I would think assuming no other forces and perfect sphere and no collapse you wouldfeel pull in all ddirections at the centre as the centre of mavity would be in the solid sphere pulling inwards from the centre and inwards from the surface. Centre of mavity would be like the surface of a sphere within the solid with object

Correct me please and explain if I'm wrong
 
I would think assuming no other forces and perfect sphere and no collapse you wouldfeel pull in all ddirections at the centre as the centre of mavity would be in the solid sphere pulling inwards from the centre and inwards from the surface. Centre of mavity would be like the surface of a sphere within the solid with object

Correct me please and explain if I'm wrong

Just forget about inwards/outwards for a second. All bodies with mass "attract" each other (mavity). There is no "outwards", just "inwards"; bodies with mass do not repel each other like magnets with the same polarity. So, at the centre of a circle (yep, forget about the sphere for a moment) the question is "for the body at the centre of circle, how much mavity is exerted upon it by each point on the circle?" It doesn't matter what the actual number is... the point is that each point on the circle "exerts" the same gravitational pull as every other point on the circle (although with different vectors). The nett effect is that 0 force is exerted on the thing in the middle of the circle (all the numbers cancel each other out).
 
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