Can You Solve 'The Hardest Logic Puzzle In The World'?

I probably should have posted a new reply, rather than update the old one.

See above edit. Does that help?
 
div0 said:
I probably should have posted a new reply, rather than update the old one.

See above edit. Does that help?
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Yeah I get that now, its a clever construct to get the same answer from both true and false Gods, well done :)

I'm still going to see if its possible without a two-part question though
 
Judgeneo said:
Yeah I get that now, its a clever construct to get the same answer from both true and false Gods, well done :)
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Good stuff :-)

I'm still going to see if its possible without a two-part question though
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In the words of Liam Neeson 'good luck'! :D



ps: I don't think it is possible.

pps: based on how long that took to write up, I hope I'm forgiven for my fairly brief attempts to previously explain from my phone!
 
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Hikari Kisugi said:
It needs a two part question, as there are too many unknowns.
Nice work div0
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Three unknowns - ja=yes/no; Identity of A, Identity of B. Third identity is implied
Three questions. So not necessarily impossible.
The only way I can get near it is by saying second or third question doesn't have to be the same for each possibility. e.g. ja ja and da da prompts question 3. ja da and da ja prompts question 4.

Anywho, I might convince myself otherwise later.
 
Jono8 said:
Why don't they all turn on the 3rd day? Why do they test it for 97 days drawing conclusions that they already know the answer to. Conclusions that they also all know that the others know the answer to.
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You're getting very confused with this... from the pov of each dragon there are either 99 or 100 (including themselves) with green eyes...

try figuring it out for 3 dragons then 4 dragons... seriously, if you're struggling with 100 then do it for 3 - maybe try solving it for 2 green eyed and 1 blue eyed dragon first...
 
dowie said:
You're getting very confused with this... from the pov of each dragon there are either 99 or 100 (including themselves) with green eyes...

try figuring it out for 3 dragons then 4 dragons... seriously, if you're struggling with 100 then do it for 3 - maybe try solving it for 2 green eyed and 1 blue eyed dragon first...
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I know how it works! But i do not agree with it.

All the dragons know that all the dragons can see at least 98 green eyed dragons. They also know that they all know that. Would you agree?
 
Try it with 3... you've said you can see it working for 2 but not greater than two - try it with three and outline your issue with it - we'll go from there
 
dowie said:
Try it with 3... you've said you can see it working for 2 but not greater than two - try it with three and outline your issue with it - we'll go from there
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I already have. Can you answer my questions? Do all the dragons know that all the dragons can see AT LEAST 98 green eyed dragons? Also, do they all know that they all know this?
 
dowie said:
yes

so what is your issue with the solution for 3 dragons?
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If this is the case. Why do the dragons not all think, on the first day " I know there are at least 98 green eyed dragons, if any dragon looks out at everyone and only sees 97 green eyed dragons, he will know he has green eyes and will leave at midnight...."
 
how will he know he has green eyes? no dragon is going to see 97 green eyed dragons - they're going to see 99... the individual dragons can only assume that the other dragons can see either 98 or 99 other green eyed dragons... their assumption is that there are either 99 or 100 in total

so I'll ask again - what is your issue with the solution for 3 dragons?
 
dowie said:
how will he know he has green eyes?
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Induction, apparently. They ALL know there are at least 98 green eyed dragons. They all know that they all know this as well. Therefore the starting point should skip to them all saying " we all know there are at least 98 green eyed dragons, if anyone looks out to see only 97 green eyed dragons, then they will know they are the 98th and turn into a sparrow at midnight".

This doesn't happen so they all know that no one looked out and saw only 97 green eyed dragons so there must be at least 99 green eyed dragons....etc
 
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yup - you still don't understand it - like I said.. start at 3 - if you struggle solving 3 then post the issue you're having
 
dowie said:
yup - you still don't understand it - like I said.. start at 3 - if you struggle solving 3 then post the issue you're having
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Can you not answer why they cannot skip straight to questioning whether anyone sees 97 green eyed dragons?

The first 97 days using the induction method are seemingly taken up with finding out information that they all know to be incorrect. Why would they do this when they already know, and know everyone else knows, that "there are at least 98 green eyed dragons".
 
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I already have.. see above - no dragon is going to see 97...

now for the umpteenth time - it will probably be easier to work through 3, then 4...

so - 3 dragons - try to figure it out otherwise post the issue you're having
 
do you want to at least attempt to understand the problem or are you just trolling?

edit- you asked me "Can you not answer why they cannot skip straight to questioning whether anyone sees 97 green eyed dragons?"

I've given you the answer - your question makes no sense - no dragon will see only 97 green eyed dragons in this problem
 
Jono8 said:
Why aren't you answering my questions? Why does it matter that no dragon will see 97 green eyed dragons in my example?
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It doesn't matter...you brought it up in the first place! I have answered your questions..

Now how about trying with 3 dragons as you're clearly not getting your head around 100?
 
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