Poll: Does 0.99 Recurring = 1

[AlphaNumeric]

Originally posted by AcidHell2
and that the maths model as some one says is made by humans and is flawed in some aspects to make it easier.

But you just said if God came down and told you 0.9r = 1 (and being God, he's not "flawed" like we are) you'd still not beleive him.

Do the thread a favour and keep quiet, because if you just stick to your guns even in the face of God him/herself, you're immune to logic.

Originally posted by piggott
eg.
2x = 5
So according to what you said, 1x = 4 right?

Let X = 2.5

2x = 5
Take x from 1 side, 2.5 from the other
x = 2.5

Looks self consisent to me? Who said x = 1? I take 1x from one side, and the value of x from the other, thats how it works.

 

[Guv]

Originally posted by AcidHell2
hence the maths model is flawed

It isn't though, it's fully understandable and the model works.


I'm arguing both sides now

 

[VDO]

Originally posted by piggott
2x = 5
So according to what you said, 1x = 4 right?

No.

2x=5
2x-x=5-x
x=5-x

1x=5-x, not 4!

 

[memphisto]

Originally posted by jokester
x = 0.9r

5x = 5*0.9r
5x = 4.9r
4x = 4
x = 1

Jokester

so what happens to the 5 ? because we all know eventually at the end of the day there is one

 

[Glaucus]

Originally posted by Guv
It isn't though, it's fully understandable and the model works.


I'm arguing both sides now

for everything apart from reacuring numbers cos there infinte, if a numbers infinite it aint finite and so cannot be a number.

 

[AlphaNumeric]

Originally posted by AcidHell2
hence the maths model is flawed

With logic like that you should be a logicstican! Its flawed because you say it is. Everyone else (and God ) says it isn't, but you stick to your views, everyone loves a stubborn person

 

[Guv]

Originally posted by memphisto
so what happens to the 5 ? because we all know eventually at the end of the day there is one

what 5?

what Jokester has said is accurate as far as i can see

 

[AlphaNumeric]

Originally posted by AcidHell2
for everything apart from reacuring numbers cos there infinte, if a numbers infinite it aint finite and so cannot be a number.

Root 2 is infinite in its decimal expansion, but its a number. Pi is infinite in its decimal expansion, but is a number. 1/7 is an infinite (recurring) decimal expansion, but its a number.

 

[memphisto]

Originally posted by Guv
what 5?

what Jokester has said is accurate as far as i can see

do it on yer calculator any number of 0.9s you want and the result is always a 5 at the end

 

[VDO]

Originally posted by memphisto
so what happens to the 5 ? because we all know eventually at the end of the day there is one

You subtract x from it.

x=0.9r
5x-4.9r
5x-x=4.9r-x
4x=4

 

[Glaucus]

Originally posted by AlphaNumeric
With logic like that you should be a logicstican! Its flawed because you say it is. Everyone else (and God ) says it isn't, but you stick to your views, everyone loves a stubborn person

im not stuborn in this case i am and will be to my grave unless any1 can show it to me in the real world which you cant, otherwise i would be agreeing.


to put it another way a value has to be finite to be a number, only numbers can be used in a mathsmodel.

.9r is infinite no ones diisagreeing with that are they??

and hence cannot be measured by its exact nature and thus cannot be a number and therfore can not work in maths with out being round to sum degree.

 

[Bakedgoods]

Alpha, im not having a go it's just I haven't seen this disproved and so on. Im just trying to learn and debate.

If 0.9r = 1

1/2 = 0.5

0.9r/2 = 0.49r?

Surely it would never actually reach 0.5?

 

[Guv]

Originally posted by memphisto
do it on yer calculator any number of 0.9s you want and the result is always a 5 at the end

how are you putting an infinite number of 9's into your calculator?

 

[Jokester]

Originally posted by Guv
If someone was to draw an accurate graph of 0.9r, surely it would never reach 1?

Sorry about the quality. It's supposed to be a flat line at y = 1



Jokester

 

[memphisto]

Originally posted by VDO
You subtract x from it.

x=0.9r
5x-4.9r
5x-x=4.9r-x
4x=4

but theres no 5 in x as x is 09r

 

[VDO]

Originally posted by memphisto
do it on yer calculator any number of 0.9s you want and the result is always a 5 at the end

You're not getting this infinity business. If you have a calculator that'll take an infinite number of 9's, Area 51 would like to see you.

 

[AlphaNumeric]

Originally posted by memphisto
do it on yer calculator any number of 0.9s you want and the result is always a 5 at the end

Not if its infinite. The last place is always a 9, because you've shown its infinite in its length of 9s (by construction).

Originally posted by Wardie
Just as a person said, if a graph was drawn of 0.9r, it shouldn't reach 1?

Graphs introduce the fact you have to show something in the real world. In maths, you don't have that constraint, so you can "push" it all the way to 0.5

 

[memphisto]

Originally posted by VDO
You're not getting this infinity business. If you have a calculator that'll take an infinite number of 9's, Area 51 would like to see you.

is he about he hasnt posted much in this thread if at all i dont think

 

[AlphaNumeric]

Originally posted by AcidHell2
im not stuborn in this case i am

Quote of the millenium!

 

[Harley]

Originally posted by AlphaNumeric
Harley, another post which was well worth the read

Thanks. When you say that about something I had to say on maths, you make my weekend

But have we decided we actually agree yet, or have we reached an armed truce?

Take a peek at my last post (starts "That's precisely where I'm coming from, though") in the original thread, if you would. We've never disagreed about the nature or validity of your proofs, but I'm interested in your thoughts on my comments about limitations, etc (the "thinking out of the box" bit ).