Poll: Does 0.99 Recurring = 1

Does 0.99 Recurring = 1

  • Yes

    Votes: 225 42.5%

  • No

    Votes: 304 57.5%
  • Total voters
    529
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Originally posted by memphisto
but the point is, the only people that would be able to offer any sort of rebuttal to your proofs / questions are other mathmaticians, which suggest that you all think you are superior to none mathmaticians.
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No it doesn't suggest anything of the sort.

It suggests that if you don't know much about maths and cannot offer anything to the table, then it's almost worthless being involved in a debate that is primarily about maths. It's like me entering a debate of the spanish civil war. I did very little history in my school years, and I wouldn't even attempt to get involved without first learning about the subject, at least a little. Once I knew a little bit about the Spanish Civil War, I could at least enter the discussion and understand what they are talking about. But could I disprove any of what each person was saying?

You talk about "mathematicians" as one large group of people. Do you not think that there are also mathematicians with philosophy degrees, or mathematicians with a degree in fine art?
 
Originally posted by Datamonkey
simple,

if you round up 0.9r then it = 1, if not it simply equates to 0.9r


end of, lol


canna believe this is going on still

of course there is a differeance between 0.9r an 1 otherwise why would we bother having a 0.9r in the first place, it's sooo much simpler to type 1 than 0.9r lol


try it, am i right or am i right???

lol :D
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its notthing to do with the fact you are rounding up.

Maths is not that simple you know

Its do with the fact that there are infinite number of 9s after the dp. They tend to limit which is one. That the real reason why 0.9r=1
 
Ok, how about I conclude this.

1.0 - 0.9, what is the answer?

1.00 - 0.99, what is the answer?

1.000 - 0.999, what is the answer?

1.0000 - 0.9999, what is the answer?

Now follow the above pattern an infinite amount of times. Can you honestly tell me that at any point during the course of the pattern, the answer ACTUALLY becomes 0.0r (0.0 recurring)? I'll agree that there is a point where the diference becomes negligible for all intents and purposes, but does it ACTUALLY BECOME EXACTLY 0.0 recurring?
 
Originally posted by Xenoxide
You have just proven yourself, Alpha, and anyone else wrong.

What you are basically saying is that 0.9r is not equal to 1, however since there is no other appropriate way of working with it, the diference is negligible. And therefore for all intents and purposes, 1 is equal to 0.9r. I will completely agree with this.

However, in actual fact 0.9r is not equal to 1, and there is a diference. This diference is infinitely small, and is therefore almost completely ignored when doing mathematics. But the diference is there.
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Not at all. You have merely inferred this.

0.999 recurring when used in equations behaves exactly like 1. If it were not equal to 1, then it would behave differently, would it not?

0.99 as an approximation behaves "a little" like one.
 
Originally posted by daz
No it doesn't suggest anything of the sort.

It suggests that if you don't know much about maths and cannot offer anything to the table, then it's almost worthless being involved in a debate that is primarily about maths. It's like me entering a debate of the spanish civil war. I did very little history in my school years, and I wouldn't even attempt to get involved without first learning about the subject, at least a little. Once I knew a little bit about the Spanish Civil War, I could at least enter the discussion and understand what they are talking about. But could I disprove any of what each person was saying?

You talk about "mathematicians" as one large group of people. Do you not think that there are also mathematicians with philosophy degrees, or mathematicians with a degree in fine art?
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but the point is that there is a philosophical argument or an alternative argument to this, and the crux of the matter is, we can probably all see your logic and reasoning behind why 0.99r = 1 mathematically. I can see the logic, i can see the equations and I can even agree that in mathematyical terms 0.99r = 1

you are all so conceited and arrogant that you cannot see that it is just as valid an opninon that 0.99r does not =1

there is no right or wrong answer.

the sooner everyone sees that the better.
 
Originally posted by AlphaNumeric
You did the wrong degree. You should be doing Mathematics, since you understand PhD level mathematics at 3rd year age, and without even going to the lectures.
To quote to link, I would like you to elaborate on (for my own peicce of mind ;))

First of all - it has a lot to do with measure theory. I assume you must obvioulsy know what a measure is. So I'm sure you wont mind telling us.

Also, a Banach Space is pretty special - they come up to. Would you be able to tell me if a Banach space was everywhere connected? (Do you even know what a vector space is?!?!)

I'm not asking much - just a couple of explinations that will show you know the VERY VERY BASICS of what that link entails
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Got to jump thru hoops? :p You could google all that anyway so it wouldn't prove much of what little I remember.

Measures are associated with sigma algebra and is mainly applied to integration which would be known as measure theory. All the fun of non nengative numbers (an overly long term for 0 or a positive number) in there too with measure spaces ;)

A banach space is a complete vector space and nope I couldn't tell you too much about them because that's all I remember of them.

A vector space is to do with adding together vectors into a vector sum as well as multiplication of vectors.

Afraid that is all I remember these days. Doesn't help that I'm rubbish at explaining them :(

It's probably not enough to give you peace of mind but it's about the best I can do from memory :)


Edit - Sheesh I only went for a drink mid typing this, and come back and there's a page and a half to catch up on
 
Originally posted by AlphaNumeric
Nope, just 55% of it
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In all fairness, how many people do you think are voting because they see Alpha and Daz, and think "Ooh, Maths and Physics, that's the team", or "In my magic world, I don't like the idea, or know the facts, so it's wrong"?

Incidently, what was your postcount (rough guess) before all this stuff started?
 
Originally posted by memphisto


you are all so conceited and arrogant that you cannot see that it is just as valid an opninon that 0.99r does not =1

there is no right or wrong answer.

the sooner everyone sees that the better.
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Well I hate to be described as conceited and arrogant when no alternative view points are put forward other than "it isn't", and I'm supposed to raise my arms and say "Oh my gosh, you're right, how could i have not seen it before. You've proven me completely wrong!"
 
Originally posted by memphisto
but the point is that there is a philosophical argument or an alternative argument to this, and the crux of the matter is, we can probably all see your logic and reasoning behind why 0.99r = 1 mathematically. I can see the logic, i can see the equations and I can even agree that in mathematyical terms 0.99r = 1

you are all so conceited and arrogant that you cannot see that it is just as valid an opninon that 0.99r does not =1

there is no right or wrong answer.

the sooner everyone sees that the better.
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Its about time you gave up on the 0.0r1 business anf agreed that maths is perfect(it always is)

As far as philosophy is concerned, maths is not remotely related to it. It has its own framework.

You can only say 0.9r doesnt equal 1 in a philosophical sense. And i wont question your logic.
 
Originally posted by carvegio
on a seperate note, I dont suppose you know any group representation theory alpha and have a spare 2 minutes?
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I am familiar with Group Theory, and homomorphisms. I do not pretend to know more than that, because its beyond the courses I've vbeen lectured. I will conceed I don't know it.
Originally posted by Haly
A vector space is to do with adding together vectors into a vector sum as well as multiplication of vectors.
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Shame multiplying vectors in the dot product isn't allowed ai?
Originally posted by Haly
A banach space is a complete vector space and nope I couldn't tell you too much about them because that's all I remember of them.
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Strange you remember all that about vector spaces, yet forget that about Banach spaces. Complete being?

Strange your replies sync up so well with Mathworld ;)
 
Originally posted by sid

You can only say 0.9r doesnt equal 1 in a philosophical sense. And i wont question your logic.
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Sure I'll agree with that too.

0.9999r is not equal to 1 in a philosophical sense.

Common sense says so.
 
Originally posted by daz
Well I hate to be described as conceited and arrogant when no alternative view points are put forward other than "it isn't", and I'm supposed to raise my arms and say "Oh my gosh, you're right, how could i have not seen it before. You've proven me completely wrong!"
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but the crux of it is that you want mathematical proof. we cant give you mathematical proof, to a question that is partially philosophical


However we can all agree in our own little way that 0.99r is not 1

you can all agree that 0.99r is 1

Or we can all agree that there are 2 different answers from two different viewpoints.

like Alpha said previously philosophically he cant prove me worng but then philosophically i Cant prove I'm right.

therefore there is no right or wrong.
 
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