Going to use x for the Pi symbol as i can't see it on my machine.
2xr^2 + 2xrh
------------ =2
4xr^2
Expanding and then substituting and cancelling
2xr(r+h) .......... r+h
--------- = --------- = 2
4xr(r) ................. r
h/r=2 h=2r
Then for the second part of the fun
xr^2h
-------- = the answer y
4/3xr^3
so using h=2r
3xr2(2r)...... 3(2r) .......... 6
--------=---------= ------ =1.5
4xr^3.......... 4r .............. 4
I think.
excellent, didnt get any of the working, but if you're right i guessed 4, so that was an incredibly amazing guess
and the pie symbol was copied from google
interesting to see if anyone else gets a different answer?![]()
Platypus has done it right in nice latex too.
Seems quite complicated for a GCSE tbh.
I suppose you need to define h for the cylinder then eliminate it?
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It's an iGCSE, apparantly much harder.
i being international
Well that explains it then. It puts our education system to shame tbh, of what I've seen of the math side of it anyway.
Just looking at the specimen paper
http://www.cie.org.uk/docs/dynamic/31227.pdf
I wonder how many grade C GCSE students could even do the first question correctly lol.
Got 9/4 too. Some A-level stuff is easier than this!
They made you retake after getting an A![]()