GCSE Maths que from today...

Soldato
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hello :)

could someone help me with this maths question that was in the IGCSE paper today? spent ages on it, and couldnt get anywhere :/

(please excuse my paint skills)



taa :)
 
Going to use x for the Pi symbol as i can't see it on my machine.

2xr^2 + 2xrh
------------ =2
4xr^2

Expanding and then substituting and cancelling
2xr(r+h) .......... r+h
--------- = --------- = 2
4xr(r) ................. r

h/r=2 h=2r


Then for the second part of the fun

xr^2h
-------- = the answer y
4/3xr^3
so using h=2r
3xr2(2r)...... 3(2r) .......... 6
--------=---------= ------ =1.5
4xr^3.......... 4r .............. 4

I think.

excellent, didnt get any of the working, but if you're right i guessed 4, so that was an incredibly amazing guess :p

and the pie symbol was copied from google ;)

interesting to see if anyone else gets a different answer? :)
 
I suppose you need to define h for the cylinder then eliminate it?

fytg0.png
 
(2*pi*r*h + 2*pi*r^2)/4*pi*r^2 = 2
=> (2*pi*r*h/4*pi*r^2)+(2*pi*r^2/4*pi*r^2)=2
=>(h/r)(2*pi*r/4*pi*r) + (2*pi*r^2/4*pi*r^2)=2
=>(h/r)(1/2) + 1/2 = 2
=>h/2r + r/2r = (h+r)/2r = 2
=>(h+r) = 4r => h=3r.

Haven't gone through the rest yet though.
 
excellent, didnt get any of the working, but if you're right i guessed 4, so that was an incredibly amazing guess :p

and the pie symbol was copied from google ;)

interesting to see if anyone else gets a different answer? :)

The answer I actually got was 1.5
Its just utterly unreadable given the forum layout
I will try to lay it out in better fashion

God GCSE maths was 20 years ago now :/

-edit worse than that, i also managed to do it wrong, lol, oops
 
paradox has done it right in nice latex too.

Seems quite complicated for a GCSE tbh.

Might just be because i've forgotten the algebra of geometry, things like the area of a circle i had to deduce from the fourmulas given rather than just knowing it as a GCSE student does. Other than that though it is just simple manipulation using algebra.
 
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I suppose you need to define h for the cylinder then eliminate it?

fytg0.png

ahh that looks about right.

shame i couldn't think of that in the exam :( yes it was quite a challenging paper... but i only missed that one out, and i know i did one other rong but meh.

yeh the Igcse is harder, and less coursework based too, tbh i prefer less coursework, although it means i have 18 exams :( half way there now! 9 to go...
 
All you need to do is sub in the formulae correctly and cancel it all out. I get the 9/4 answer as P4radox.

2= (2pi r h + 2pi r^2)/(4pi r^2) = (h + r)/(2r)
so: h + r = 4r, h = 3r
then:
ratio = (3pi r^2 h)/(4pi r^3) = (3h)/(4r)
sub in h = 3r
ratio = (3*3r)/(4r) = 9/4


edit: But although this kind of question does seem rather easy to me now, I suppose it's these core skills that need to be built to do A-level maths, even if at A-level maths is a slightly different subject (imo). This question is quite a good test of whether a candidate can cancel and substitute effectively.
 
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Well that explains it then. It puts our education system to shame tbh, of what I've seen of the math side of it anyway.

Just looking at the specimen paper

http://www.cie.org.uk/docs/dynamic/31227.pdf

I wonder how many grade C GCSE students could even do the first question correctly lol.

hmm thats a different board to what we do, we do edexcel IGCSE, that CIE paper looks slightly harder, but not impossible
 
Got 9/4 too. Some A-level stuff is easier than this!

yeh exactly... I actually did the paper last year too, but missed the A* by 0.5% :/ even after a remark :mad:

so the school made me retake this year.

AS WELL as doing the ADD maths course, which is all algebra, and I have that exam on Monday, apparently some of it is harder than A level stuff.

got 13% in my mock for that :cool:

hopefully the paper on friday for gcse will be easier :/
 
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