Is my maths right?

Soldato
Joined
12 Jun 2005
Posts
5,361
God, this seems so blimming simply but i think i have done it wrong.

If I had event A happening 100 times and event B happening 100 times.

And the percentage of A was 55% and the percentage of B was 45%. (of another variable)

If I wanted to change the results of how much event a was happing from 55% to 50% and event B to 50%.

Would this be right

event A happening = (100 / 55) *50
event B happening = (100 / 45) *45

.....this sounds really confusing i know....

Can anyone understand?

EDIT:

Ok erm, for instance:

If there the word "man" and the word "woman" was mentioned 100 times each in a book.

And the percentage of males was 55% and the percentage of females was 45%.

Assuming there is a link between two things (eg males linked to the word man..etc..).

If I was actually 50:50 males to females, how would the number of times the word "man" and "woman" be affected.
 
Last edited:
I don't really understand what you are asking. When you mean Event A happening 100 times, you mean it occured 100 times? Like you rolled a 4 on a die 100 times?

But then you have the percentage of A and B?!?

If you clarify i should be able to help
 
55% of the time A is happening, therefore:

55% of A is 100.

To get to 100% of A, you need to divide 100 by 55%:

100/0.55 = 182 (to 0 decimal places)

To get to 50% of A, you then multiply 182 by 50%

182 * 0.5 = 91 (to 0 decimal places).



Remember, 55% is not 55, you need to use 0.55.
 
Ok erm, for instance:

If there the word "man" and the word "woman" was mentioned 100 times each in a book.

And the percentage of males was 55% and the percentage of females was 45%.

Assuming there is a link between two things (eg males linked to the word man..etc..).

If I was actually 50:50 males to females, how would the number of times the word "man" and "woman" be affected.
 
Last edited:
Sorry for my sluggish replies, lady troubles!

So this is my interpretation: When loading people onto plane it was found that by loading 100 people into the rear and 100 people in the front, the weight was distributed 55% over the rear wheels and 45% over the front.
How many people should be loaded onto the rear and front to divide the weight 50-50?

That is your question, yes?


But do you want the same total? Ie 200 people?
 
God, this seems so blimming simply but i think i have done it wrong.

If I had event A happening 100 times and event B happening 100 times.

And the percentage of A was 55% and the percentage of B was 45%. (of another variable)

If I wanted to change the results of how much event a was happing from 55% to 50% and event B to 50%.

Would this be right

event A happening = (100 / 55) *50
event B happening = (100 / 45) *45

.....this sounds really confusing i know....

Can anyone understand?

EDIT:

Ok erm, for instance:

If there the word "man" and the word "woman" was mentioned 100 times each in a book.

And the percentage of males was 55% and the percentage of females was 45%.

Assuming there is a link between two things (eg males linked to the word man..etc..).

If I was actually 50:50 males to females, how would the number of times the word "man" and "woman" be affected.

Eh?

What do you mean "and the percentage of males was 55% and the percentage of females was 45%"?

If what was actually 50:50 males to females? Are you talking about a statistical distribution and the probability of getting 50 males and 50 females from a sample of 100 given the probability of getting each male and female is 0.55 and 0.45?

What is it you want to know?:confused:
 
What is it you want to know?:confused:

Where to put the people on the plane ;)

So this is my interpretation: When loading people onto plane it was found that by loading 100 people into the rear and 100 people in the front, the weight was distributed 55% over the rear wheels and 45% over the front.
How many people should be loaded onto the rear and front to divide the weight 50-50?
 
55% - 45% = 10% - the difference in value between both sides

10 / 2 = 5% - this is the amount of change both sides has to have (5% more on 1 side, 5% less on the other) so that they are equal

200 / 100 = 2 - this is the value of 1%

2 * 5 = 10 people - this is 5%

So: Take 10 people from the rear of the 'plane, and move them to the front: leaving 90 at the rear, and 110 at the front.

.... right?
 
Back
Top Bottom