Random Knowledge / Facts

Women can't touch their elbows behind their backs.


... works better if you're actually stood in front of them when you say it :(
 
For every epsilon greater than zero, there exists a delta greater than zero such that, whenever |x-c|<delta, we necessarily have |f(x)-f(c)|<epsilon if and only if f is a continuous function.

For any triangulated surface topologically equivalent to a sphere, the number of the faces plus the number of vertices is always 2 greater than the number of edges. There is a generalisation of this for all orientable and non-orientable surfaces, but I won't go into it now.

If a function f:U->Rn (U open in Rn) is smooth, and the derivative of f at x0 is invertible, then there exist neighbourhoods U' of x0 in Rn, V' of f(x0) in Rn such that f|:U'->V' is a diffeomorphism.
 
You've failed because you haven't related remotely to your audience and your fact has fallen on deaf ears. Happy New Years Fail.
 
SlyReaper said:
For every epsilon greater than zero, there exists a delta greater than zero such that, whenever |x-c|<delta, we necessarily have |f(x)-f(c)|<epsilon if and only if f is a continuous function.

For any triangulated surface topologically equivalent to a sphere, the number of the faces plus the number of vertices is always 2 greater than the number of edges. There is a generalisation of this for all orientable and non-orientable surfaces, but I won't go into it now.

If a function f:U->Rn (U open in Rn) is smooth, and the derivative of f at x0 is invertible, then there exist neighbourhoods U' of x0 in Rn, V' of f(x0) in Rn such that f|:U'->V' is a diffeomorphism.
Click to expand...

Every time you talk about maths, someone buys a baseball bat.
 
SlyReaper said:
For every epsilon greater than zero, there exists a delta greater than zero such that, whenever |x-c|<delta, we necessarily have |f(x)-f(c)|<epsilon if and only if f is a continuous function.

For any triangulated surface topologically equivalent to a sphere, the number of the faces plus the number of vertices is always 2 greater than the number of edges. There is a generalisation of this for all orientable and non-orientable surfaces, but I won't go into it now.

If a function f:U->Rn (U open in Rn) is smooth, and the derivative of f at x0 is invertible, then there exist neighbourhoods U' of x0 in Rn, V' of f(x0) in Rn such that f|:U'->V' is a diffeomorphism.
Click to expand...

I raise you
If 1 < p < \infty, p^{-1}+q^{-1} = 1, f \in L^{P}(X,S,\mu) and g \in L^{q}(X,S,\mu), then fg \in L^{1}(X,S,\mu) and |\int fg d\mu| \leq \int | fg|d\mu \leq ||f||_{p}||g||_{q}.

Name that inequality
 
Sawell said:
Women can't touch their elbows behind their backs.


... works better if you're actually stood in front of them when you say it :(
Click to expand...

Do you mean we can't make both our elbows meet at the back? Cos I most certainly can touch my elbow behind my back :p

But yah, they don't meet. I'm assuming that men can do it then?
 
It's illegal to release gray squirrels into the wild.

In Canada it's illegal to disembark from a moving aircraft without a parachute.

A 12" record isn't quite 12 inches, that;s the size of the sleeve.

CDs play from the middle out, the opposite to most records.

The smoothest surface ever to be discovered on earth is Patrick Stewart's head.

Film Critic Mark Commode has a Phd in Film.
 
One of the ancient wonders of the world, the Mausoleum of Maussollos was destroyed by earthquakes and parts of it were used to build Bodrum Castle in Turkey.
 
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platinum87 said:
no its because mavity bends light.


my fact about 2 objects moving faster than light i will rephrase it

the distance between these objects has increased, if you work out the speed which they are moving apart, it is (lets say) 2.6x the speed of light

(this is to kill whoever said 2 spaceships go 0.6 light speed in different directions)
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The distance between two objects can't increase at a rate of 2.6c from any frame.

The maximum rate at which the distance between any two objects can increase is 2c, and even this can only be achieved if the two objects happen to be photons moving away from each other in opposite directions.

Still, this doesn't change the fact that nothing can travel faster than light ;)
 
tisonlyme said:
My chest doesn't get pushed out when I do it :confused:

Even if it did, most men I know have far more impressive boobies than me to be honest! :D
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That's impossible! The elbows behind the back trick is the oldest and perviest trick I know. There's no way out of unsuspecting boobies being thrusted into the the magician's general direction.

I have actually done it many times, the funny thing is that you women do like a challenge, even when we're all falling about laughing most of you think we're laughing because you can't do it, and try harder as a result!

I'm gonna go wash my dirty little mind now.
 
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