Urgent - puzzle needs solving!

Van_Dammesque said:
In what way?
Throwing an object upwards provides a force downwards, for every reaction there is an equal and opposite reaction.
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Aye, the force of throwing the coin upwards would be more then equal to that of the three coins on their own and would have course cause the bridge to collapse.
 
Helium_Junkie said:
The force would be equal to the weight of the coin? And since one coin is always in the air that force is still not over the two coin limit....
I have no idea about physics, so correct me please :p
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The weight of jack and three coins is too much for the bridge.
The weight of jack and two coins is enough.
Juggling requires the coins to be thrown upwards, so the action of throwing the coin upwards (juggling) equates to a force downwards, proportional to the accel of the coin, now assuming mavity is like what we have on earth, then then the reactionary force must be large since the third coin will be in the air for a fraction of a second.
F=ma, so the more quickly you have to juggle the more force is required, that force upon the bridge will be MORE than the weight of the third coin, and so the bridge will collapse. (the force has to be greater than mavity even before the coin will leave your hand)
Little experiment for you all ;) Stand on your bathroom scales, now pick up a weight (say a can of beans), throw the can of beans into air and at the same time watch the weight, it will briefly shoot up and then back down to your original weight.
The force of juggling is in addition to the weight of the coin.
Oh and of course the force required to catch a coin too!
 
There aint much point looking closely into the physics involved, you are correct that the juggling will still cause excessive forces, but so would walking across the bridge if his weight alone is too much.
 
Boycie said:
Juggle them
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You know there is a simpler explanation why juggling wont work. The OP said he can't throw the coins. Juggling involves throwing them. So no juggling in the first place.
 
Hate said:
the answer is simple.

if he can't throw the third then he throws the first or second...
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Since this is a logic puzzle, and it specifically said that he can't throw the third coin across, I'm inclined to agree with you...
 
okay the answer is...
he ties one coin to the start of the rope bridge he then crosses the bridge without it falling .

the villagers then all run onto the bridge true to all action films involving a bridge the end you just walked on collapses . the villagers all die jack then drags the brigde back up from his side and retrieves the coin. :p
 
Mr.Clark said:
Since this is a logic puzzle, and it specifically said that he can't throw the third coin across, I'm inclined to agree with you...
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no. 'the third' is just a loose way of saying the coin that is not part of the 2 that he carries, as any coin could be the third coin, if he can not carry three coins then he can only select 2 to carry, there is always going to be a third coin, and the riddle does not say the coins are different weights.

so whatever coin is in question, will always be 'the third' coin.
 
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Tie a piece of string to a coin, leave the coin next to the bridge, cross holding the other end of the string and 2 coins, pull the third coin across once you've crossed.
 
The riddle does not say there is string to play with, i believe that we are limited to what is mentioned in the riddle . i think the key is with the villagers, or its a play on words.
 
hargi said:
boycie Whats that book you got called
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Not at home atm but i bought it from debenhams a couple of years ago, its pocket sized and they do a whole series of them, not sure if they do them now but i have seen a similar selection in waterstones and borders. Will have a scout and post back.

Cheers
luke

EDIT: This isnt the same book but its by the same author and there is a series of 4 i think.
 
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chirst sake.. "How many forum members does it take to solve a riddle?"

The riddle has been solved, Mr. Dog "Pedant" oid, in the first post. It's as old as houses.
 
Dj_Jestar said:
chirst sake.. "How many forum members does it take to solve a riddle?"

The riddle has been solved, Mr. Dog "Pedant" oid, in the first post. It's as old as houses.
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haha, alright but the answer was squashed by some very elaborate physics , something to do with up force and that
 
Dogoid said:
no. 'the third' is just a loose way of saying the coin that is not part of the 2 that he carries, as any coin could be the third coin, if he can not carry three coins then he can only select 2 to carry, there is always going to be a third coin, and the riddle does not say the coins are different weights.

so whatever coin is in question, will always be 'the third' coin.
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incorrect.

its a variation of an age old puzzle thats like 2 coins add up to 30p, one isn't a 20p...

the answer to the puzzle is 20p and 10p.

"one isn't a 20p thou?"
"no, the other one is."

the third coin in this instance could be stuck to something, hence unable to throw it.
 
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