If you go for 8 on a single 80cm fan you'll have a few choices.
1) 2 sets of 4 LEDs per string.
+ve ------LED------LED-------LED-------LED------ -ve
Each LED would share the 12v and receive 3v each. This may not be desireable as the LEDs I showed were...
Forward Voltage : 3.2v – 3.8v
..and may not achieve full brightness.
So you'd need..
2) 4 sets of 2 LEDs per string.
+ve ----resistor------LED------LED------ -ve
Now each LED is 3.5v typical, so that's 7v total string voltage needed. 12v - 7v = 5v to drop by resistor at 20mA which would require a 250 ohm resistor.
3) Or individually resistor each LED.
12v - 3.5v = 8.5v to dissipate at 20mA. 8.5/0.02 = 425 ohm or nearest standard value.
Or go for
12 LEDs per fan by having 4 strings of 3 LEDs each for the perfect solution given the parts you have purchased.
3.5v x 3 = 10.5v, leaving only 1.5v@20mA to dissipate by resistor. 1.5/0.02 is 75 ohm, so I dropped it to 56 ohm which was a nearby standard value.
And would end up looking something (but better than) like this (quick photoshop colour change)
With resistors you can combine them to make different resistances.
eg.
in series
--resistor---resistor--resistor--
has the effect of adding together. 56 + 56 + 56 = 168ohm.
or in parallel
_/--resistor--\____
..\--resistor--/
which just gets complicated.